Math, asked by devansh1422795, 1 year ago

Find the value of a and b if, 7-3√2/7+3√2= a-b√2.​

Answers

Answered by sreedeviaddepal
1

Answer:

Given (7-3√2)/(7+3√2)

on rationalizing the denominator with its conjugate i.e., by multiplying the numerator and denominator with (7-3√2)

\frac{7-3\sqrt{2}}{7+3\sqrt{2} }×\frac{7-3\sqrt{2}}{7-3\sqrt{2} }

(7-3√2)^2/49-18⇒ (49+18-42√2)/31

on comparing with a-b√2 we get a =67/31 and b= 42/31

Step-by-step explanation:

Answered by kesar2005
0

Answer:

Given (7-3√2)/(7+3√2)

on rationalizing the denominator with its conjugate i.e., by multiplying the numerator and denominator with (7-3√2)

\frac{7-3\sqrt{2}}{7+3\sqrt{2} }×\frac{7-3\sqrt{2}}{7-3\sqrt{2} }

(7-3√2)^2/49-18⇒ (49+18-42√2)/31

on comparing with a-b√2 we get a =67/31 and b= 42/31

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