Find the value of a and b if, 7-3√2/7+3√2= a-b√2.
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Answer:
Given (7-3√2)/(7+3√2)
on rationalizing the denominator with its conjugate i.e., by multiplying the numerator and denominator with (7-3√2)
\frac{7-3\sqrt{2}}{7+3\sqrt{2} }×\frac{7-3\sqrt{2}}{7-3\sqrt{2} }
(7-3√2)^2/49-18⇒ (49+18-42√2)/31
on comparing with a-b√2 we get a =67/31 and b= 42/31
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Answered by
0
Answer:
Given (7-3√2)/(7+3√2)
on rationalizing the denominator with its conjugate i.e., by multiplying the numerator and denominator with (7-3√2)
\frac{7-3\sqrt{2}}{7+3\sqrt{2} }×\frac{7-3\sqrt{2}}{7-3\sqrt{2} }
(7-3√2)^2/49-18⇒ (49+18-42√2)/31
on comparing with a-b√2 we get a =67/31 and b= 42/31
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