Math, asked by HAsubra8mingh, 1 year ago

Find the value of a and b, if 7+3√5/3+√5 - 7-3√5/3-√5 = a + √5b

Answers

Answered by Golda
636
7+3√5/(3+√5) - 7-3√5/(3-√5) a + √5b
= (7+3√5)(3-√5) - (7-3√5)(3+√5)/(3+√5)(3-√5) = a + √5b
21-7√5+9√5-15-21-7√5+9√5+15/9-5 = a + √5b
4√5/4 = a + √5b
√5 = a + √5b
Comparing both left and right hand side a = 0 and b = 1
Thus a = 0 and b= 1  answer.
Answered by aarushrocks2
55

Answer:

a=0,b=1

Step-by-step explanation:

7+3√5/(3+√5) - 7-3√5/(3-√5) a + √5b

= (7+3√5)(3-√5) - (7-3√5)(3+√5)/(3+√5)(3-√5) = a + √5b

21-7√5+9√5-15-21-7√5+9√5+15/9-5 = a + √5b

4√5/4 = a + √5b

√5 = a + √5b

after seeing both left and right hand side a = 0 and b = 1

Hence a = 0 and b= 1  answer.

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