Question

find the value of a and b if 7+√5/7-√5=a+b√5​

Answer 1

Answer:

Step-by-step explanation:

$(7+\sqrt{5})/(7-\sqrt{5})=a+b\sqrt{5}\\ (7+\sqrt{5})*(7+\sqrt{5})/(7-\sqrt{5} )*(7+\sqrt{5} )=a+b\sqrt{5} \\ (49+5+14\sqrt{5})/(49-5)= a+b\sqrt{5}\\ 54+14\sqrt{5}=44(a+b\sqrt{5})\\ 2(27+7\sqrt{5})=44(a+b\sqrt{5}) \\ \\27+7\sqrt{5} /22=a+b\sqrt{5}\\ a=27/22 b=7/22$

Answer 2

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