Find the value of a and b if P(1) = 1 and P(2) = 7 in the polynomial P(x)=2x 3 – ax 2 +7x – b.
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Answer:
a = 5
b = 3
Step-by-step explanation:
P(x) = 2x³ - ax² + 7x - b
For P(1) = 1
substitute 1 as the value of x
P(1) = 2(1)³ - a(1)² + 7(1) - b = 1
= 2 - a + 7 - b = 1
a+b = 2+7-1
a+b = 8 .........eq1
For P(2) = 7
substitute 2 as the value of x
P(2) = 2(2)³ - a(2)² + 7(2) - b = 7
= 2(8) - a(4) + 7(2) - b = 7
16 - 4a + 14 - b = 7
4a + b = 16 + 14 - 7
4a + b = 23........eq2
eq1 and eq2
4a + b = 23 ...eq2 solve simultaneously
a + b = 8 ...eq1
-----------------
subtract eq1 from eq2
3a = 15
a = 15/3
a = 5
from eq1
a + b = 8
5 + b = 8
b= 8-5
b= 3
a=5 , b=3
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