Find the value of a and b if they are the zeroes of P(x) = x2 + as + b.
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1
Answer:
P(x)=x²+ax+b
P(a)=0
P(a)=a²+a²+b
P(a)=2a²
P(b)=0
P(b)=b²+ab+b
therefore,
P(a)=P(b)
2a²=b²+ab+b
2a²-ab=b²+b
2a(a-b)=b(b+1)
2a(a-b)-b(b+1)=0
(2a-b)(a-b)(b+1)=0
therefore, a=0 and b=0....
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Answer:
Thank u
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