Find the value of a and b if under root 2+1 by under root 2-1 - under root 2-1 by under root 2+1=a+under root 2 b
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Step-by-step explanation: We have to rationalise both the terms on LHS--
√2+1/√2-1 * √2+1/√2+1 - √2-1/√2+1 * √2-1/√2-1
= (√2+1)²/(√2)²-1 - [(√2-1)²/(√2)²-1 ]
= 3+2√2/1 - [ 3-2√2/1 ]
= 3+2√2 - 3+2√2
=4√2 = a+√2b
So, a=0 and b=4
Smarty566:
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