Find the value of a and b so that the polynomial x³ - 4x² +ax+b is exactly divisible by x–2 aswell as x + 1.
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Given
- A polynomial x²-4x²+ax+b
- and have factor x-2 and X+1
To find
- Value of a and b
Solution
- From the remainder Therom
let g(X) = x-2 and x-1
g(X)=0
=>X=2
p(X) =x²-4x²+ax+b
=>p(2) = 4-16+2a+b
=>0=2a+b-12
=>2a+b = 12. ---------> (1)
Let g(X) =1
p(1) = 1-4+a+b
=>0=a+b-3
=>a+b=3 -------> (2)
Now From Equation (1) and (2)
a+b = 3
2a+b =12
_______
a=9
Now putting the value of a in Equation 1
9+b =3
b = -6
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