Question

on principal of ₹2000 interest of 2year is ₹100then rate of interest is _____pcpa​

Answer 1

Answer:

Rate of interest = 2.5%

Step-by-step explanation:

P = 2000

n = 2

I = 100

r = r

2000 × r × 2/100 = 100

40r = 100

r = 100/40

r = 2.5%

Check ⇒

P = 2000

n = 2

I = 100

r = 2.5%

2000 × 2 × 2.5/100 = 100

40 × 2.5 = 100

100 = 100

L.H.S = R.H.S

Hence, verified.

The answer is correct.

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Answer 2

✬ Rate = 2.5% p.a ✬

Step-by-step explanation:

Given:

• Principal (p) is Rs 2000.
• Time (t) is 2 years
• Interest (I) is Rs 100
• Rate (R) of interest p.a ?

To Find:

• What is the rate of interest (R) = ?

Formula to be used:

• I = P x R x T/100

Solution: Putting the values on formula we get

$\implies{\rm }$ 100 = 2000 x R x 2/100

$\implies{\rm }$ 100 = 4000R / 100

$\implies{\rm }$ 100 x 100 = 4000R [ By cross multiplication ]

$\implies{\rm }$ 10000 = 4000R

$\implies{\rm }$ 10000/4000 = R

$\implies{\rm }$ 10/4 = R

$\implies{\rm }$ 2.5% = R

Hence, The rate of interest is 2.5% per annum.

___________

★ ChEck ★

→ P x R x T/100 = I

→ 2000 x 2.5 x 2/100= 100

→ 4000 x 2.5/100 = 100

→ 1000/100 = 100

→ 100 = 100 { LHS = RHS }