find the value of a and b.solve this for 20 marks
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Hey mate!
Here's ur answer dear :-)
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![\frac{2 \sqrt{6} - \sqrt{5} }{3 \sqrt{5} - \sqrt{6} } = a + b \sqrt{30} \\ \\ \frac{2 \sqrt{6} - \sqrt{5} }{3 \sqrt{5} - \sqrt{6} } \times \frac{3 \sqrt{5} + \sqrt{6} }{3 \sqrt{5} + \sqrt{6} } \\ \\ \frac{2 \sqrt{6} (3 \sqrt{5} + \sqrt{6}) - \sqrt{5}( 3 \sqrt{5} + \sqrt{6})}{(3 \sqrt{5} ) {}^{2} - ( \sqrt{6} ) {}^{2} } \\ \\ \frac{6 \sqrt{30} + 12 - 15 - \sqrt{30} }{45 - 6} \\ \\ \frac{5 \sqrt{30} - 3}{39} \\ \\ a = - 3 \: \: \: \: \: b = \frac{5}{39} \sqrt{30} \frac{2 \sqrt{6} - \sqrt{5} }{3 \sqrt{5} - \sqrt{6} } = a + b \sqrt{30} \\ \\ \frac{2 \sqrt{6} - \sqrt{5} }{3 \sqrt{5} - \sqrt{6} } \times \frac{3 \sqrt{5} + \sqrt{6} }{3 \sqrt{5} + \sqrt{6} } \\ \\ \frac{2 \sqrt{6} (3 \sqrt{5} + \sqrt{6}) - \sqrt{5}( 3 \sqrt{5} + \sqrt{6})}{(3 \sqrt{5} ) {}^{2} - ( \sqrt{6} ) {}^{2} } \\ \\ \frac{6 \sqrt{30} + 12 - 15 - \sqrt{30} }{45 - 6} \\ \\ \frac{5 \sqrt{30} - 3}{39} \\ \\ a = - 3 \: \: \: \: \: b = \frac{5}{39} \sqrt{30}](https://tex.z-dn.net/?f=+%5Cfrac%7B2+%5Csqrt%7B6%7D++-++%5Csqrt%7B5%7D+%7D%7B3+%5Csqrt%7B5%7D++-++%5Csqrt%7B6%7D+%7D++%3D+a+%2B+b+%5Csqrt%7B30%7D++%5C%5C++%5C%5C+%5Cfrac%7B2+%5Csqrt%7B6%7D++-++%5Csqrt%7B5%7D+%7D%7B3+%5Csqrt%7B5%7D++-++%5Csqrt%7B6%7D+%7D+++%5Ctimes+%5Cfrac%7B3+%5Csqrt%7B5%7D++++%2B++%5Csqrt%7B6%7D+%7D%7B3+%5Csqrt%7B5%7D+++%2B+++%5Csqrt%7B6%7D+%7D+++%5C%5C++%5C%5C++%5Cfrac%7B2+%5Csqrt%7B6%7D+%283+%5Csqrt%7B5%7D+++%2B+++%5Csqrt%7B6%7D%29+-+%5Csqrt%7B5%7D%28+3+%5Csqrt%7B5%7D+++%2B+++%5Csqrt%7B6%7D%29%7D%7B%283+%5Csqrt%7B5%7D+%29+%7B%7D%5E%7B2%7D+-+%28+%5Csqrt%7B6%7D+%29+%7B%7D%5E%7B2%7D++%7D+%5C%5C++%5C%5C++%5Cfrac%7B6+%5Csqrt%7B30%7D++%2B+12+-+15+-++%5Csqrt%7B30%7D+%7D%7B45+-+6%7D++%5C%5C++%5C%5C++%5Cfrac%7B5+%5Csqrt%7B30%7D++-+3%7D%7B39%7D++%5C%5C++%5C%5C+a+%3D++-+3+%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A+b+%3D++%5Cfrac%7B5%7D%7B39%7D++%5Csqrt%7B30%7D+)
Hope it helps!
[ I don't know it's right or wrong]
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Here's ur answer dear :-)
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Hope it helps!
[ I don't know it's right or wrong]
☺☺☺
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hey u are in class 11th?
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