Question

find the value of A, B and C​

Answer 1

Answer:

sum all angles in a triangle=180°

sum of angles on a straight line=180°

• firstly in ∆ADC( let the point where tangent is droped be D).Let angle ADC be x so, now
• 60°+70°+x=180°
• 180°-130°=x
• x=50°
• so angle c is 50°
• now b+c=180°
• b+50°=180°
• b=130°
• now in∆ABD
• 30°+130°+a=180°
• a=180°-160°
• a=20°
• so,a=20,b=130,c=50

Answer 2

Answer:

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