Question

FIND THE VALUE OF A, B AND C.
AB×BA= (B+1)CB

Answer 1

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AB×BA = (B + 1)CB

2 digit number multiplied by 2 digit number gives answer 3 digit

17 × 71 gives 4 digit answer

so number is less than 17

13 × 31 = 403 = (3+1)03

C = 0

A = 1

B = 3