There are three persons aged 60, 65 and 70 years old. The survival probabilities for these three
persons for another 5 years are 0.7, 0.4 and 0.2 respectively. What is the probability that at least two
of them would survive another five years?
Answers
probability that at least two of them would survive another five years = 0.388
Step-by-step explanation:
Probability of Surviving 60 Year aged = 0.7
Probability of not Surviving 60 Year aged = 1 - 0.7 = 0.3
Probability of Surviving 65 Year aged = 0.4
Probability of not Surviving 65 Year aged = 1 - 0.4 = 0.6
Probability of Surviving 70 Year aged = 0.2
Probability of not Surviving 70 Year aged = 1 - 0.2 = 0.8
Probability that atleast two survived
= 60 , 65 survived + 60,70 Survived + 65, 70 survived + 60,65, 70 survived
= (0.7)(0.4)(0.8) + (0.7)(0.2)(0.6) + (0.4)(0.2)(0.3) + (0.7)(0.4)(0.2)
= 0.224 + 0.084 + 0.024 + 0.056
= 0.388
probability that at least two of them would survive another five years = 0.388
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