Find the value of A,B and C if : 45A-CB7=284..
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a x b = 2
b = 2/a
Substitute in b x c = 24
2/a x c = 24
2c = 24a
c = 12 a
Substitute in c x a = 3
12a x a = 3
12a^2 = 3
a^2 = 3/12 = 1/4
a = 1/2
Substitute in a x b = 2
1/2 x b = 2
b = 2 x2 = 4
Substitue in b x c = 24
4 x c = 24
c = 24/4 = 6
a + b + c = 1/2 + 4 + 6 = 10.5
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