Question

find the value of A B and C such that the numbers a 7 B 23 and C are in AP​

Answer 1

by doing a2-a1= (23-B)

23-B=B-7

2B=30 B=15

now new AP = 7,15,23,C

now a=7

d=8

so 4th term= a +3d

7+3(8)= 24+7=31

C=31 B=15