find the value of A B and C such that the numbers a 7 B 23 and C are in AP
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by doing a2-a1= (23-B)
23-B=B-7
2B=30 B=15
now new AP = 7,15,23,C
now a=7
d=8
so 4th term= a +3d
7+3(8)= 24+7=31
C=31 B=15
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