Find the value of A,B,C
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Let the ratio be 1x/2, 2x/3, 3x/4
It is given that the sum of the numbers in the ratio is 276
So,
1x/2 + 2x/3 + 3x/4 = 276
[(6×1x)+(4×2x)+(3×3x)] /12 = 276
( 6x + 8x + 9x ) / 12 = 276
23x / 12 = 276
x = 276 × 12 / 23
x = 12 × 12
x = 144
Thus, the numbers are
1) 1x/2 = 144/2 = 72
2) 2x/3 = 144×2/3 = 96
3) 3x/4 = 144×3/4 = 108
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