find the value of a for which polynomial x 4 - x cube - 11 x square - X + a is divisible by X + 3
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Answered by
69
If f(x) is divisible by x+3
Then,
x+3 = 0
x= -3
Now,
f(x)= x⁴-x³-11x²-x+a
f(-3)= (-3)⁴- (-3)³- 11(-3)²-(-3)+a
0= 81-(-27)- 11(9) +3+a
0= 81+27-99+3+a
0= 108-99+3+a
0= 111-99+a
0= 12+a
a= -12
HOPE, IT HELPED U!!!
Then,
x+3 = 0
x= -3
Now,
f(x)= x⁴-x³-11x²-x+a
f(-3)= (-3)⁴- (-3)³- 11(-3)²-(-3)+a
0= 81-(-27)- 11(9) +3+a
0= 81+27-99+3+a
0= 108-99+3+a
0= 111-99+a
0= 12+a
a= -12
HOPE, IT HELPED U!!!
abhinav646:
thanks
wlcm
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