Question

. Find the value of 'a' for which the following equations
have equal roots.
i) x2 + (a + 3) x + a +6 = 0
ii) 2(a + 1).x2 + 2(a + 3) x + a +5 = 0​

Answer 1

Answer:

1

Step-by-step explanation:

Given equation is: kx(x−2)+6=0

kx² −2kx+6=0

Then a=k,b=−2k,c=6

Then b² −4ac=0

So (−2k)² −4k(6)=0

4k² −24k=0

4k(k−6)=0

k=0 and k=6

Put value of k

Then 6x² −12x+6=0

6x²  −6x−6x+6=0

6x(x−1)−6(x−1)=0

∴x=1

Answer 2

Answer:

Given equation is: kx(x−2)+6=0

kx² −2kx+6=0

Then a=k,b=−2k,c=6

Then b² −4ac=0

So (−2k)² −4k(6)=0

4k² −24k=0\

4k(k−6)=0

k=0 and k=6

Put value of k

Then 6x² −12x+6=0

6x²  −6x−6x+6=0

Hope u got it

pls mark me the brainliest

thank u