. Find the value of 'a' for which the following equations
have equal roots.
i) x2 + (a + 3) x + a +6 = 0
ii) 2(a + 1).x2 + 2(a + 3) x + a +5 = 0
Answers
Answered by
2
Answer:
1
Step-by-step explanation:
Given equation is: kx(x−2)+6=0
kx² −2kx+6=0
Then a=k,b=−2k,c=6
Then b² −4ac=0
So (−2k)² −4k(6)=0
4k² −24k=0
4k(k−6)=0
k=0 and k=6
Put value of k
Then 6x² −12x+6=0
6x² −6x−6x+6=0
6x(x−1)−6(x−1)=0
∴x=1
Answered by
1
Answer:
Given equation is: kx(x−2)+6=0
kx² −2kx+6=0
Then a=k,b=−2k,c=6
Then b² −4ac=0
So (−2k)² −4k(6)=0
4k² −24k=0\
4k(k−6)=0
k=0 and k=6
Put value of k
Then 6x² −12x+6=0
6x² −6x−6x+6=0
Hope u got it
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