If |x2 - 2x - 8| + |x2 + x - 2| = 3|x + 2|, then the set of all
real values of x is
(1)[1,4] U {-2) (2)[1,4]
(3)[-2,1] U [4,00) (4)(-00, -2] [1,4]
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ANSWER
(sinα)x
2
−2x+b≥2⇒(sinα)x
2
−2x+b−2≥0
4−4(b−2)sinα<0⇒b>
sinα
1
+2
As −1≤sinα≤1⇒−1≤
sinα
1
≤1
⇒1≤2+
sinα
1
<3⇒1<b≤3
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