Find the value of ‘a’ for which the following points A(a, 3), B(2,1) and C(5, a) are collinear.
Hence, find the equation of the line.
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Answer:
a²-4a-4=0
Step-by-step explanation:
As we know in Geometry
Area of Triangle in Geometry= (1/2) [x₁ (y₂ – y₃ ) + x₂ (y₃ – y₁ ) + x₃(y₁– y₂)]
If the points are collinear then Area =0
=> [x₁ (y₂ – y₃ ) + x₂ (y₃ – y₁ ) + x₃(y₁– y₂)]=0
=>[a (1 – a) + 2 (a – 3 ) + 5(3– 1)]=0
=>2a-a²+2a-6+10=0
=>a²-4a-4=0
equation of the line
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