Question

Find the value of a for which the quadtric equation 4y^2-3ay+1=0hs equal roots.

Answer 1

Heya Friend!!!


Here's ur ans with solution :)

▶ 4y² - 3ay + 1 = 0

➡As we know that the quadratic equation has real and equal roots if when the discriminant is equal to zero.

that is D = 0


and also,

D = b² - 4xc ......( i )

here,

x = 4

b = -3a

c = 1


putting the value in equation ( i )

D = b² - 4xc

0 = ( -3a )² - 4 × 4 × 1

0 = 9a² - 16

16 = 9a²

$\frac{16}{9} = {a}^{2}$

$\sqrt{ \frac{16}{9} } = a$

$\frac{4}{3} = a$


So,

✴the value of a is 4/3

for which the equation has real and equal roots.