find the value of 'a'for which the root αand β of the equation x^2-6x+a=0. satisfy the realtion 3α+2β=20
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Polynomial P(x) = x² - 6 x + a
Given α and β are the roots. To find a , if 3 α + 2 β = 20. ---(1)
From the quadratic expression:
α + β = 6 ---(2)
and α β = a --- (3)
Multiply equation (2) by 2 and subtract from (1) to get:
α = 20 -12 = 8
Substitute this value in(2) to get:
β = 6-8 = -2
Substitute these in (3) to get: a = α β = -16.
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Anonymous:
Welcome brother
Answered by
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α + β = 6
β = 6- a
3α + 2β = 28
3α + 2(6-a) = 20
α = 20 - 12
α = 8
substituting x= 8 in the equation
64 - 48 + a = 0
a = - 16
hope it helped you
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