Question

Find the value of ‘a” for which the system of equations 3x + 2y – 4 = 0 and ax – y – 3 = 0, will represent intersecting lines​

Answer 1

Answer:

answer for the given problem is given

Answer 2

Answer:

a ≠$\frac{-3}{2}$

Step-by-step explanation:

For 2 lines to be intersecting, their slopes must not be same.

We first represnt the lines in the form of y=mx+c, whwere m is the slope .

Given:

3x + 2y-4=0

or 2y= -3x+4

or y= -$\frac{3}{2} x$ +4

So $m_{1}$ = -3/2

Similarly

ax - y-3 =0

or y= ax-3

So $m_{2}$= a

For intersecting lines, $m_{1}$≠ $m_2$

Therefore a ≠ -$\frac{3}{2}$

So the lines will intersect for all real values of a except -3/2

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