Question

Find the value of 'a' for which (x-1) is a factor of the polynomial a²x²-4ax+4a-1 (detailed answers needed)

Answer 1

a^2x^2-4ax+4a-1=o
a^2+4a+4a-1=0
a^2+8a-1=0 then apppy quadratic formula

Answer 2

Heya buddy,
here is your answer,


p(x) = ax²-4ax+4a-1


x-1 = 0 ( as given that it is the factor )
=> x = 1
so x = 1

p(1) = a²(1)²-4a(1)+4a-1
= a²-4a+4a-1
= a²-1

a²-1 = 0 (since factor= 0)
=> a² = 1
=> a = √1
=> a = 1



Hope this help
as u had mention i had written it directly but if u want it in detail just message me i will edit the answer.



thank you


-Sneha