Question

Find the value of a for which (x-4) is a factor of ( 2x3-3x2-18x+a)

Answer 1

x-4=0 <=> x=4 now,putting this value in 2x^3-3x^2-18x+a,we have 2(4)^3-3(4)^2-18(4)+a=0 2×64-3×16-18×4+a=0 128-48-72+a=0 128-120+a=0 a=-8

Answer 2

hey Mate

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