find the value of a,if:2a=(2/ x minus x)sq
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The value of a is (4+x⁴ - 4x²) /2x²
Step-by-step explanation:
(2/x - x)²
= (4/x²) + x² - 2.(2/x).x [∵ (a-b)= a²+b² -2ab]
= (4/x²) + x² -4
= (4+x⁴ - 4x²) / x² [The L.C.M. is x²]
According to the problem,
2a = (4+x⁴ - 4x²) / x²
so, a = (4+x⁴ - 4x²) / x² * 2
or, a = (4+x⁴ - 4x²) /2x²
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