Find the value of $A$ if the $4$-digit number $3A5A$ is divisible by both $3$ and $5$.
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sorry ....wrong question..
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The value of A is 5 and the number is 3555.
1) Given 4 digit number 3A5A , the number is divisible by both 3 and 5.
2) A number is divisible by 3 if the sum of all its digits is divisible by 3 .
3) Sum of digits of the given number is 3+A+5+A = 8+2A.
4) A number is divisible by 5, only if its unit or one's digit is 5 or 0.
5) Hence, A can have values only 5 or 0.
6) putting value 5 in equation, 8+ 2*5 = 18 which is divisible by 3.
7) Putting value 0 in equation, 8+2*0 = 8 which is not divisible by 3.
8) Hence, the value of A is 5.
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