Question

find the value of a, if the distance between the points A(-3,-14) and B(a,-5) is 9 units​

Answer 1

Step-by-step explanation:

given : a(-3,-14), b (a, -5 ) are vertices

if distance between AB vertices = 9 unit

BY Applying distance Formula we get

AB^2=(x2-x1)^2+(y2-y1)^2

9^2= (a+3)^2+(-5+14)^2

81= (a+3)^2 + 81

0= (a+3)^2

a+3 = +-0

a= -3

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