Question

find the value of 'a' if the polynomial 2x^2+ax^2+3x-5 and x^3+x^2-4x a leave the same remainder when divided by(x-1)
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Answer 1

Answer:

-13/3

Step-by-step explanation:

Let the given polynomials be f(x) and g(x).

ATQ,

When f(x) and g(x) are divided by (x-2) they leave the same remainder.

I.e (x-2) is a factor of f(x) and g(x). It means 2 is the zero of f(x) and g(x)

So that,

f(2) = g(2)

2x³+ax²+3x-5 = x³+x²-4x+a

2(2)³+a(2)²+3(2)-5 = 2³+2²-4(2)+a

2(8)+a(4)+6-5 = 8+4-8+a

16+4a+1 = 4+a

17+4a = 4+a

4a-a = 4-17

3a = -13

a = -13/3.