Math, asked by lalnunhlui78, 4 days ago

Find the value of 'a' if x-1 is a factor of p(x)=4x³+3x²-4x+a

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Answers

Answered by koreanboy
10

Step-by-step explanation:

Let P(x)=4x

3

+3x

2

−4x+k

Given, (x−1) is a factor of P(x)

x−1=0

x=1∴ p(1)=4×(1)

2

+3×(1)

2

−4×(1)+k=0

4+3−4+k=0

k+3=0

k=−3

Hence, the value of k is −3.

Answered by IlMYSTERIOUSIl
7

Required Answer :-

• In the question we have to Find the value of 'a'

• If x-1 is a factor of p(x)=4x³+3x²-4x+a

so ,

{\sf{:\implies x - 1 = 0 }}

{\sf{:\implies x  = 1}}

Now ,

{\sf{:\implies p(x) =  {4x}^{3}  + {3x}^{2} - 4x  + a  }}

by putting the value of x as 1

{\sf{:\implies p(1) =  {4(1)}^{3}  + {3(1)}^{2} - 4(1)  + a  }}

{\sf{:\implies p(1) =  {4}  + {3} - 4+ a  }}

{\sf{:\implies p(1) =  3+ a  }}

{\sf{:\implies 0=  3+ a  }}

{\sf{:\implies a=   - 3 }}

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