Question

in the given figure, D and E are the points on the
base BC of AABC such that BD = CE,
AD = AE. Prove that AABE = AACD.​

Answer 1

Explanation:

Given = BD=CE

AD=AE

Prove = ∆ABE=∆ACD

Proof=

BD=CE. (given)

If we add DE on both the sides then,

BD+DE = CE+DE

BE = DC. [EQ.1]

DA = AE. (given). [EQ.2]

As DA=AE, then the angle form in front of line will be same .. So,

angle ADE=AED. [EQ.3]

So, by EQ 1 ,2,and 3 ....

We can say that

∆ABE= ∆ ACD

PLZZZ MARK ME AS BRAINLIST.....