Math, asked by A2004, 1 year ago

Find the value of a if x+6 is a factor of x^3+3x^2+4x+a. Also find the other factors.

Answers

Answered by priyasingh123

We need to apply the Factor Theorem here.
We solve for the x of the g(x)
x+6=0
x=−6x
Now that we have the value of x, we substitute it.
x^3+3x^2+4x+a=0

(−6)^3+3(−6)^2+4(−6)+a=0

−216+3(36)+4(−6)+a=0
Next, we multiply the numbers to their coefficients.
−216+108−24+a=0
Since we have to find the value of a, we put the a on the other side or all the other numbers on the other side. In this case, let’s put all the other numbers on the other side.
a=216−108+24
a=216−132
a=84
Therefore, the value of a is 84.

HOPE IT HELPS ❤❤

priyasingh123: You have asked for the value of 'a'

A2004: I also asked about other factors...

priyasingh123: ohhh sorry... if it's wrong then report it

priyasingh123: Bt can you tell me what type of other factor

priyasingh123: In this question we can find the value of a factor only

priyasingh123: There's no any other factor

priyasingh123: can tell me where is the other factor??? ur question is wrong

A2004: I found it...

A2004: It's ok....

Yusuf2005: a=216−108+24
a=216−132
a=84 This is wrong because how -108+24 makes 132

Answered by bedmutthasejal2

Answer:

Step-by-step explanation:

a=84

A2004: BT wht about other factors....

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