find the value of a if x+a is a factor of i)x^3+ax^2-2x+a+4
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x - a is a factor of
{x}^{3} - ax {}^{2} + 2x + a - 1x
3
−ax
2
+2x+a−1
we know,
x - a = 0
x = 0+a = a
Substitung the value of x as a,
we have,
(a)^3 - a(a)^2 + 2(a) + a - 1 =0
a^3 - a^3 + 2a + a - 1=0
3a - 1=0
3a =1
a = 1/3
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