Question

find the value of a,if x³-ax²+bx-a is exactly divisible by (x+2)​

Answer 1

Answer:

Step-by-step explanation:

p(x) = x^3 - ax^2 + bx- a.

x + 2 is a factor of p(x) ---> p(- 2) = 0

---> - 8 - 4a - 2b- a = 0

---> 5a = -2b - 8

---> a =-2(b + 4)/5

x^3 - ax^2 +bx - a =

= (x + 2)(5x^2 - 2(b - 1)x + b + 4)/5