Question

find the value of a in the following (3^5-^2) (4^5+3^2)​

Answer 1

√(3)+√(2)√(3)-√(2) = a + b√(6)

✓ √(3)+√(2)√(3)-√(2) = a + b√(6) (√(3)+√(2))^2 (√(3)-√(2)) (√(3)+√(2)) = a + b√(6) 3 + 2 + 2√(6)3 - 2 = a + b√(6) 5 + 2√(6) = a + b√(6) a = 5 & b = 2

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