Question

Find the value of a k if, (x-1) is a factor of p(x) = kx²-8x+k
Find the value of a k if, (x-1) is a factor of p(x) = kx²-8x+k​

Answer 1

Answer:

let g(x)=x-1

if g(x)=0

x-1=0 then x= 1

put the values of x in p(x)

k*1^2-8*1+k=2k-8

let p(x)=0 root of eq

then 2k-8=0

2k=8

k=4

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Answer 2

Answer:

1) p(x) = kx²-8x+k

(x-1) is factor of this equation

x-1=0

x= 1 so put the value of x into the equation

p(1) = k(1²) -8(1) +k

= k-8+k=0

= 2k=8

= k= 8/2

= k = 4