Question

find the value of 'a' so that 3y-1 is factor of polynomial 8y^4 + 4y^3 - 16y^2 + 10y + a​

Answer 1

f( x) = 8y⁴+ 4y³- 16y²+10y+a=0

g( x) = 3y-1=0

or, 3y= 1

or, y=1/3

Therefore,

 f( x)= 8y⁴+ 4y³- 16y²+ 10y+a=0

or,f(1/3)=8×(1/3)⁴+4×(1/3)³-16×

(1/3)²+10×1/3+a =0

or, 8×1/81+4×1/27-

.               16×1/9+10/3+a=0

or, 8/81+4/27-16/9+10/3+a=0

or, 8+12-144+270+81a/81=0

or, 106+ 81a/ 81=0

or, 106+ 81a=81

or, 81a= 81-106

or, 81a= - 25

or, a= -25/81

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