Question

if (3k+1, 2k-5) is a solution of the equation 2x-y +66. Find K

Answer 1

Since, (3k + 1, 2k - 5), is a solution. So, x = 3k + 1 and y = 2k - 5.

Now, solve

2x - y + 66 = k

k = 2 (3k + 1) - 2k - 5 + 66

k = 6k + 2 - 2k - 5 + 66

k = 4k + 63

4k - k = 63

3k = 63

k = $\frac{63}{3}$

k = 21

Please mark my answer brainliest.