Question

Find the value of A so that the point (3,a) lie on the line 2x-3y=5

Answer 1

${\bf{\purple{Hola!!}}}$

2x-3y=5

2(3)-3(a)=5

6-3a=5

5-6=-3a

-1=-3a

a=${\frac{-1}{-3}}$

${\bf{\red{a={\frac{1}{3}}}}}$

Verifying our answer:-
2(3)-3(${\frac{1}{3}}$)=5
6-1=5

$5=5$

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Answer 2

step by step explaination