Find the value of a so that x = -3, y = 2 is a solution of the equation 4ax + 9(2+ ay) = 0.
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x=-3;y=2
4ax + 9(2+ay)=0
now,subsituting the values,
4a(-3) + 9(2+a(2))=0
-12a + 9(2+2a)=0
-12a + 18 + 18a=0
6a + 18=0
6a=-18
a=-3
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