Question

Find the value of 'a' such that ( 3x -1 ) is a factor of f (x) = 6( x cube ) + a( x square ) + x - 2

Answer 1

Step-by-step explanation:

we know that 3x-1 is factor of f(x) = 6x³ + ax² + x- 2

Therefore ,

By using factor therorm f(x) = 0

now ,

6(1/3)³ + a(1/3)² + 1/3 - 2 = 0

6/27 + a(1/9) + 1/3 -2 = 0

2/9 + a (1/9) + 1/3 - 2 = 0

a = 2 - 1/3 + 9 - 2/9

a = -1/3

Hope its helpful to you ...