Find the value of (a) such that x-4 is the factor of 5x^3-7x^2-ax -28
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given p(x)= 5x^3-7x^2-ax-28
(x-4) is a factor of 5x^3-7x^2-ax-28
=>p(4)=0
=>5(4)^3-7(4)^2-4a-28=0
=>320-112-4a-28=0
=>-4a=-180
=>a=180/4
=>a=45
(x-4) is a factor of 5x^3-7x^2-ax-28
=>p(4)=0
=>5(4)^3-7(4)^2-4a-28=0
=>320-112-4a-28=0
=>-4a=-180
=>a=180/4
=>a=45
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