Question

find the value of 'a' when g(t) = t+3 is a factor of p(t) = t²+2at-2a+3

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Answer 1

Step-by-step explanation:

(t+3)2 +2at-2a+3

(2t±3)2+2at-2a+3

4t2+9+12t + 2at-2a+3

4t2+12+

Answer 2

Step-by-step explanation:

since g(t)=t+3

so -3 must be the zero of p(t)

p(t)= t^2+2at-2a+3

p(-3)= 9 + 18a -2a+3

9+18a-2a+3=0

9+16a+3=0

12+16a=0

16a= -12

a= -12/16

= -3/4