Question

Find the value of a when g(x) is a factor of P
(1) g(x)= x+1; p(x)= x2 + ax + 2​

Answer 1

since g(x) is a factor of p(x) ,
Root of g(x)
X+1= 0
x=-1

So,
p(-1)= (-1)(-1) + a(-1) +2
= 1-a+2
=3-a

Now since g(x) is a factor of p(x),
3-a=0
-a=-3
Hence, a=3