find the value of 'a' when x³ + x² + x + a is divisible by x-1/2
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if x-1/2 divides x³+x²+x+a
then x-1/2 is a factor of x³+x²+x+a
so x-1/2=0
=>x=1/2,qa zero of x³+x²+x+a
put the value x =1/2 in x³+x²+x+a
we get 1/8+1/4+1/2+a=0
= >7/8+a=0
=>a=-7/8
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