xv. Solve it please.Help me
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Step-by-step explanation:
XV.
Given :-
a+b+c = 0
To find :-
Evaluate a³+b³+c³ ?
Solution :-
Given that
a+b+c = 0
=> a+b = -c ----------(1)
On cubing both sides then
=> (a+b)³ = (-c)³
=> a³+b³+3ab(a+b) = -c³
=> a³+b³+3ab(-c) = -c³ (from (1))
=> a³+b³-3abc = -c³
=> a³+b³+c³-3abc = 0
=> a³+b³+c³ = 3abc
Therefore a³+b³+c³ = 3abc
Answer:-
If a +b+c = 0 then a³+b³+c³ = 3abc
Used formulae:-
- (a+b)³ = a³+b³+3ab(a+b)
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