find the value of A1 & A2
A1-A2 = -bq0/m
A1+A2 = -q0
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The given expression will be minimum, when a
1
=a
2
=a
3
=...a
n
.
Now, it is given that
a
1
.a
2
.a
3
...a
n
=1
Hence, a
i
n
=1
Since a
i
is Real, therefore a
i
=1
Hence, (1+a
1
+a
1
2
)(1+a
2
+a
2
2
)...(1+a
n
+a
n
2
)
=(1+a
i
+a
i
2
)
n
=3
n
.
Hope it's helps..♦️⚡⬆️
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