Question

find the value of a²+b²+c²-ab-bc- ca,when a=3,b=2, and c=1​

Answer 1

Answer:

Multiply by 2 (both RHS and LHS)

2( a² + b² + c² - ab - bc - ca ) = 0

=> 2a² +2 b² + 2c² - 2ab - 2bc - 2ca = 0

=> a² + b² - 2ab + b² + c² - 2bc + a² + c² - 2 ca =0

=> (a-b)² + (b-c)² + (c-a)² = 0

Now, sum of three positive numbers can not be zero there fore all the numbers are zero.

=> a = b = c

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

a²+b²+c²-ab-bc-ca

a=3, b=2, c=1

3²+2²+1²-(3×2) -(2×1) -(1×3)

9+4+1-6-2-3

3

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