Question

find the value of a3+b3-3abc,given that a=3,b=2 and c=1 for class 6 ​

Answer 1

Answer:

(3)3+(2)3 -3×3×2×1

27+8-18

35-18

17

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Answer 2

I got it as 17

Step-by-step explanation:

a= 3 so a^3 =3^3 =27

b=2 so b^3=2^3 =8

C=1 so 3abc = 3*3*2*1=18

a^3+b^3-3abc=27+8-18=17