Find the value of a³+b³+c³ - 3abc when (a+b+c) = 10 and a²+b²+c²= 50.
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a+b+c = 10
(a+b+c)² = a²+b²+c²+2(ab+bc+ca) = 100
ab+bc+ac
Now,
= (a³+b³+c³-3abc)
= (a+b+c)
= (a²+b²+c²-ab-bc-ca)
= 10 (50-25)
= 500-250
= 250
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