Find the value of (a⁴-b⁴), given that (a²+b²) = 130, (a-b) = 2 and (a+b) 16.
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Answer itself is given by you☺️☺️..
a4 - b4 =( a2)^2 -( b2)^2.— Equation 1.
This is similar to a2-b2 which results in (a-b)(a+b) but the only thing is here a and b became a2 and b2.
Break equation 1 as per the formula and you will get:-
(a2-b2)(a2+b2)
Now second bracket can't be touched at the moment but first bracket clearly shows that it can be broken similarly on the formula hence…
(a+b)(a-b)(a2+b2)…
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